JEE MAIN - Physics (2022 - 28th July Morning Shift - No. 19)
In a Young's double slit experiment, a laser light of 560 nm produces an interference pattern with consecutive bright fringes' separation of 7.2 mm. Now another light is used to produce an interference pattern with consecutive bright fringes' separation of 8.1 mm. The wavelength of second light is __________ nm.
Răspuns
630
Explicaţie
$$\lambda = 560 \times {10^{ - 9}}$$
$${B_1} = 7.2 \times {10^{ - 3}}$$
$${B_2} = 8.1 \times {10^{ - 3}}$$
$${{{B_1}} \over {{B_2}}} = {{{\lambda _1}} \over {{\lambda _2}}}$$
$$ \Rightarrow {\lambda _2} = {{560 \times {{10}^{ - 9}} \times 8.1 \times {{10}^{ - 3}}} \over {7.2 \times {{10}^{ - 3}}}}$$
$$ = 6.3 \times {10^{ - 7}}$$ m
$$ = 630$$ nm